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Copy pathsets_mysolution.py
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705 lines (590 loc) · 13 KB
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#1
def que1():
a = [1, 2, 2, 3, 4, 4, 5]
return set(a)
# print(que1())
#2
def que2():
my_set = {1, 2, 3}
element = 2
return element in my_set
# print(que2())
#3
def que3():
a = {1, 2, 3}
element = 4
a.add(element)
return a
# print(que3())
#4
def que4():
my_set = {1, 2, 3}
a=2
my_set.remove(a) if a in my_set else None
return my_set
# print(que4())
#5
def que5():
my_set = {1, 2, 3}
element = 5
my_set.discard(element)
return my_set
# print(que5())
#6
def que6():
my_set = {1, 2, 3, 4, 5}
return len(my_set)
# print(que6())
#7
def que7():
my_set = set()
return True if my_set==set() else False
#or return not my_set True if empty, False otherwise
# print(que7())
#8
def que8():
a = set()
return a
# print(que8())
#9
def que9():
a = "hello"
return set(a)
# print(que9())
#10
def que10():
t = {1, 2, 3}
n=5
return n not in t
# print(que10())
#11
def que11():
t = {1, 2, 3}
t.clear()
return t
# print(que11())
#12
def que12():
a = (1, 2, 3, 2, 4)
return set(a)
# print(que12())
#13
def que13():
a = {1, 2, 3}
return a.pop() #deletes a randomn element
# print(que13())
#14
def que14():
a = [1, 'hello', 3.14, True]
return set(a)# as True is consedered as 1 whivh is also persent so removed duplicated items
# print(que14())
#15
def que15():
a = "the cat sat on the mat"
return set(a.split())
# print(que15())
#16
def que16():
set1 = {1, 2, 3}
set2 = {4, 5, 6}
return len(set1)==len(set2)
# print(que16())
#17
def que17():
a = 5
return set(range(1,a+1))
# print(que17())
#18
def que18():
a = ['user@email.com', 'admin@email.com', 'user@email.com']
return set(a)
# print(que18())
#19
def que19():
return set((i for i in range(1,11) if i %2==0))
# print(que19())
#20
def que20():
a = my_set = {1, 2, 3, 4}
return all(i for i in a if i>0)
# print(que20())
#21
def que21():
return set("aeiou")
# print(que21())
#22
def que22():
str1 = 'hello'
str2 = 'world'
return set(str1) | set(str2)
# print(que22())
#23
def que23():
return set((x**2 for x in range(1,6)))
# print(que23())
#24
def que24():
a = "hello"
seen=set()
for i in a:
if i in seen:
return True
seen.add(i)
return False
# print(que24())
#25
def que25():
a = {'a': 1, 'b': 2, 'c': 3}
return set(a.keys())
# print(que25())
#26
def que26():
a = {'a', 'b', 'c', 'e', 'f'}
return set((i for i in a if i.lower() not in "aeiou"))
# print(que26())
#27
def que27():
a = {42}
return len(a)==1
#print(que27())
#28
def que28():
a = ['file1.txt', 'file2.pdf', 'file3.txt', 'file4.jpg']
return set(("."+i.split(".")[-1] for i in a))
# print(que28())
#29
def que29():
a = "john"
b="python"
return set(a) & set(b)
# print(que29())
# 30. Create a set of prime numbers less than 20
def que30():
a = range(2, 20)
primes = set()
for i in a:
is_prime = True
for j in range(2, int(i**0.5) + 1): # check divisibility up to sqrt(i)
if i % j == 0:#if a number has a divisor, at least one of them must be ≤ √i.
is_prime = False
break
if is_prime:
primes.add(i)
return primes
# print(que30()) # Output: {2, 3, 5, 7, 11, 13, 17, 19}
#31
def que31():
a = {1, 2}
elements = [3, 4, 5]
a.update(elements) #must me a iterble
return a
# print(que31())
#32
def que32():
a = {1, 2, 3}
return a.copy()
# print(que32())
#33
def que33():
a = [1, 2, 3, 4, 5]
return len(set(a))==len(a)
#print(que33())
#34
def que34():
a = {1, 2, 3, 4, 5}
# return {i for i in a if i % 2 != 0}
# by filter
return set(filter(lambda x:x%2==0,a))
# print(que34())
#35
def que35():
a = ['cat', 'dog', 'elephant', 'fox']
return {len(i) for i in a} #it is a set generator obj
# print(que35())
#36
def que36():
a = {1, -2, 3, 4}
return any(i for i in a if i>0)
# print(que36())
#37
def que37():
a = 12321
return set(str(a))
# print(que37())
#38
def que38():
a = {3, 7, 1, 9, 5}
return f"max {max(a)} , min {min(a)}"
# print(que38())
#39
def que39():
a = ['apple', 'banana', 'cherry', 'avocado']
return {i[0] for i in a}
# print(que39())
#40
def que40():
a = {'hello', 'world', 'python'}
return all(i.isalpha( ) for i in a)
# print(que40())
#41
def que41():
set1 = {1, 2, 3}
set2 = {3, 4, 5}
return set1 | set2
# print(que41())
#42
def que42():
set1 = {1, 2, 3}
set2 = {2, 3, 4}
return set1 & set2
# print(que42())
#43
def que43():
set1 = {1, 2, 3, 4}
set2 = {3, 4, 5}
return set1 -set2
# print(que43())
#44
def que44():
set1 = {1, 2, 3}
set2 = {3, 4, 5}
print(set1.symmetric_difference(set2))#or
return set1 ^ set2
# print(que44())
#45
def que45():
set1 = {1, 2}
set2 = {1, 2, 3, 4}
print(set1.issubset(set1))
return set1 <= set2
# print(que45())
#46
def que46():
set1 = {1, 2, 3, 4}
set2 = {2, 3}
print(set1.issuperset(set2))#or
return set1 >= set2
# print(que46())
#47
def que47():
set1 = {1, 2, 3}
set2 = {4, 5, 6}
return set1.isdisjoint(set2)# does nt work with multiple 2 each time
# print(que47())
#48
def que48():
set1 = {1, 2,}
set2 = {3, 4}
set1.update(set2) # it is like a union + update or use |=
return set1
# print(que48())
#49
def que49():
set1 = {1, 2, 3}
set2 = {2, 3, 4}
set1 &= set2 #intersection_update() or &=
return set1.intersection_update(set2) #it will give none as it will modify in plase same as &=
# print(que49())
#50
def que50():
set1 = {1, 2, 3, 4}
set2 = {3, 4}
set1-=set2
return set1.difference_update(set2)
#print(que50())
#51
def que51():
sets = [{1,2,3}, {2,3,4}, {2,3,5}]
return set.intersection(*sets)# npacking sets
# print(que51())
#52
def que52():
numbers = {1, 2, 3, 4, 5, 6}
return {i for i in numbers if i%2==0}
# print(que52())
#53
def que53():
return {i**2 for i in range(1,11) if i % 2 ==0 }
#print(que53())
#54
def que54():
set1 = {1, 2, 3}
set2 = {3, 4, 5}
set1 ^= set2
return set1
# print(que54())
#55
def que55():
set1 = {1, 2}
set2 = {1, 2, 3}
return set1 < set2
# print(que55())
#56
def que56(a = [[1, 2], [2, 3], [3, 4, 1]]):
l=[]
for i in a :
if isinstance(i,list ):
l.extend(que56(i))
else:
l.append(i)
return set(l)
# print(que56())
#57
def que57():
sets = [{1, 2}, {2, 3}, {3, 4}]
return set.union(*sets)
# print(que57())
#58
def que58():
set1 = {1, 2, 3, 4}
set2 = {3, 4, 5, 6}
a=set1&set2
set1-=a
set2-=a
return set1,set2
# print(que58())
#59
def que59():
sets = [{1}, {1, 2}, {1, 2, 3}]
return all(s1 < s2 for s1, s2 in zip(sets, sets[1:]))
# print(que59())
#60
def que60():
a =[{1, 2}, {2, 3}, {4, 5}]
return set.union(*a)
# print(que60())
#61
def que61():
data = {1, 2, 3, 4, 5}
blacklist = {2, 4}
return data-blacklist
# print(que61())
#62
def que62():
set1 = {1, 2, 3, 4}
others = [{2, 3}, {3, 5}]
return set1.difference(*others)
# print(que62())
#63
def que63():
a = {1, 2, 3}
set2 = {2, 3, 4}
return f"only in set 1 {a-set2} common {a& set2} only in set2 {set2-a}"
# print(que63())
#64
def que64():
sets = [{1, 2}, set(), {3, 4}]
return not all(sets)#or return any(not s for s in sets)
# print(que64())
#65
def que65():
a = [{1}, {1, 2, 3}, {1, 2}]
return max(a,key=len)
# print(que65())
#66
def que66():
dir1 = {'file1.txt', 'file2.pdf'}
dir2 = {'file3.txt', 'file4.jpg'}
ex={"."+i.split(".")[-1] for i in dir1 if "." in i}
ex2={"."+i.split(".")[-1] for i in dir2 if "." in i}
return set.intersection(ex,ex2)
# print(que66())
#67
def que67():
emails = {'user@gmail.com', 'admin@yahoo.com'}
valid = {'gmail.com', 'outlook.com'}
return {e for e in emails if e.split("@")[-1] in valid}
# print(que67())
#68
def que68():
post1_tags = {'python', 'coding', 'tutorial'}
post2_tags = {'python', 'programming', 'tutorial'}
return post1_tags & post2_tags
# print(que68())
#69
def que69():
role1 = {'read', 'write'}
role2 = {'read', 'execute'}
return role1 & role2
# print(que69())
#70
def que70():
user_permissions = {'read', 'write', 'execute'}
required = {'read', 'write'}
# return True if user_permissions & required == required else False
#or can be done with is subbset or superset
return required <user_permissions
# print(que70())
#71
def que71():
user1_friends = {'Alice', 'Bob', 'Charlie'}
user2_friends = {'Bob', 'Charlie', 'David'}
return user1_friends & user2_friends
# print(que71())
#72
def que72():
job1 = {'Python', 'SQL'}
job2 = {'Python', 'JavaScript', 'SQL'}
return job1 | job2
# print(que72())
#73
def que73():
store1 = {'laptop', 'mouse'}
store2 = {'laptop', 'keyboard'}
return f" available everywhere {store1 & store2}"
# print(que73())
#74
def que74():
recipe1 = {'flour', 'eggs', 'milk'}
recipe2 = {'flour', 'sugar'}
return f"all_ ingredients {recipe1 & recipe2}"
# print(que74())
#75
def que75():
votes_for = {'Alice', 'Bob'}
votes_against = {'Charlie'}
all_members = {'Alice', 'Bob', 'Charlie', 'David'}
return f"abstained {all_members - (votes_for | votes_against)}"# witthhout function it is faster
#print(que75())
#76
def que76():
enrolled = {'Math101', 'Physics101'}
conflicts = [{'Math101', 'Math102'}, {'Physics101', 'Chemistry101'}]
return any(enrolled & c for c in conflicts)
# print(que76())
#77
def que77():
completed = {'Math101', 'Physics101'}
course_prereqs = {'Math201': {'Math101'}, 'Physics201': {'Physics101', 'Math101'}}
# it mean s that for key subject a person require to have the values subjects
available = {i for i in course_prereqs if course_prereqs[i] <= completed}
return f"course available {available}"
# print(que77())
#78
def que78():
content_keywords = {'python', 'programming', 'tutorial'}
user_interests = {'python', 'data science'}
return f" relevence score = {len(content_keywords & user_interests)}"
# print(que78())
#79
def que79():
available_features = {'age', 'income', 'education'}
important_features = {'age', 'income'}
# return f"selected_features = { available_features & important_features}" if important_features <= available_features else None
# or the best way
selected = available_features & important_features
return f"selected_features = {selected}" if selected else None
# print(que79())
#80
def que80():
user1 = {'movie1', 'movie2'}
user2 = {'movie2', 'movie3'}
# Jaccard similarity=∣A∪B∣/∣A∩B∣
p = len(user1 & user2) / len(user1 | user2)
return f" similarity = {p :.2f}"#:.2f formatting specifier
# print(que80())
#81
def que81():
a = [1, 2, 3]
return { frozenset(a) : "value"}# to use list as key for dixct
# print(que81())
#82
def que82():
sets = [frozenset({1, 2}) , frozenset({2, 3})]
return set.intersection(*map(set, sets))
# print(que82())
#83
def que83():
s = {1, 2, 3}
# start with empty set in a set
pset = {frozenset()}
for elem in s:
pset |= {subset | {elem} for subset in pset} # add elem to each existing subset
return pset
# print(que83())
#84
def que84():
a = 0
return 0
#print(que84())
#85
def que85():
a = {1,2,3,4,5}
sets = [{1,2,3}, {2,4}, {3,4}, {4,5}]
return 0
#print(que85())
#86
def que86():
a = 0
return 0
#print(que86())
#87
def que87():
a = 0
return 0
#print(que87())
#88
def que88():
a = 0
return 0
#print(que88())
#89
def que89():
a = 0
return 0
#print(que89())
#90
def que90():
a = 0
return 0
#print(que90())
#91
def que91():
a = 0
return 0
#print(que91())
#92
def que92():
a = 0
return 0
#print(que92())
#93
def que93():
a = 0
return 0
#print(que93())
#94
def que94():
a = 0
return 0
#print(que94())
#95
def que95():
a = 0
return 0
#print(que95())
#96
def que96():
a = 0
return 0
#print(que96())
#97
def que97():
a = 0
return 0
#print(que97())
#98
def que98():
a = 0
return 0
#print(que98())
#99
def que99():
a = 0
return 0
#print(que99())
#100
def que100():
a = 0
return 0
#print(que100())